## Algebra 2 Common Core

$–p – \frac{2q}{3}$
First, we make the last term have the common denominator of $3$: = $–\frac{p}{3} –\frac{2p}{3} + \frac{q}{3} – \frac{3q}{3}$ Now we combine like terms and put the fractions in simplest form: =$–\frac{3p}{3} – \frac{2q}{3}$ =$–p – \frac{2q}{3}$