## Algebra 2 Common Core

$\frac{41}{4}$
We begin by substituting in the given variable values: $\frac{5[2(-2)-3]-3(-2+4)}{3(-2)+2}$ Then we simplify. It is important to keep track of the negatives and keep in mind the order of operations. Multiply and divide first and then add and subtract. $\frac{5[2(-2)-3]-3(-2+4)}{3(-2)+2}$=$\frac{5[-4-3]-3(2)}{-6+2}$=$\frac{5[-7]-6}{-4}$=$\frac{-35-6}{-4}$=$\frac{-41}{-4}$=$\frac{41}{4}$