Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 1 - Expressions, Equations, and Inequalities - 1-3 Algebraic Expressions - Practice and Problem-Solving Exercises: 42

Answer

$\frac{41}{4}$

Work Step by Step

We begin by substituting in the given variable values: $\frac{5[2(-2)-3]-3(-2+4)}{3(-2)+2}$ Then we simplify. It is important to keep track of the negatives and keep in mind the order of operations. Multiply and divide first and then add and subtract. $\frac{5[2(-2)-3]-3(-2+4)}{3(-2)+2}$=$\frac{5[-4-3]-3(2)}{-6+2}$=$\frac{5[-7]-6}{-4}$=$\frac{-35-6}{-4}$=$\frac{-41}{-4}$=$\frac{41}{4}$
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