Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - Chapter Test - Page 673: 3


$$(0, -.5)$$

Work Step by Step

Using the distance formula, we find: $$\sqrt{\left(1-\left(-1\right)\right)^2+\left(5-\left(-6\right)\right)^2}\\ 5\sqrt{5}$$ Using the midpoint formula, we find: $$\left(\frac{1-1}{2},\:\frac{5-6}{2}\right) \\ (0, -.5)$$
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