Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - Chapter Test - Page 673: 2

Answer

$$\left(6,\:5\right)$$

Work Step by Step

Using the distance formula, we find: $$\sqrt{\left(8-4\right)^2+\left(8-2\right)^2}\\ 2\sqrt{13}$$ Using the midpoint formula, we find: $$\left(\frac{8+4}{2},\:\frac{8+2}{2}\right)\\ \left(6,\:5\right)$$
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