## Algebra 2 (1st Edition)

Substituting the first equation into the second one we get: $x^2+4(0.5x-3)^2-4=0\\x^2+4(0.25x^2-3x+9)-4=0\\x^2+x^2-12x+36-4=0\\2x^2-12x+32=0\\x^2-6x+16=0\\$ This equation has a negative discriminant, thus no solution exists.