Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - 9.7 Solve Quadratic Systems - Guided Practice for Examples 1 and 2 - Page 659: 4


no solution

Work Step by Step

Substituting the first equation into the second one we get: $x^2+4(0.5x-3)^2-4=0\\x^2+4(0.25x^2-3x+9)-4=0\\x^2+x^2-12x+36-4=0\\2x^2-12x+32=0\\x^2-6x+16=0\\$ This equation has a negative discriminant, thus no solution exists.
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