## Algebra 2 (1st Edition)

Substituting the second equation ($y=7-2x$) into the first one we get: $4x^2-(7-2x)^2-32x-2(7-2x)=-59\\4x^2-(49-28x+4x^2)-32x-14+4x=-59\\(4x^2-4x^2)+(28x-32x+4x)+(-49-14+59)=0\\-4=0$ This is never true, thus there is no solution.