## Algebra 2 (1st Edition)

$$x^2+\sqrt{5}x-3x-3\sqrt{5}$$
Expanding the equations by multiplying each term in parenthesis by each of the other terms in the other set of parenthesis, we find: $$xx+\sqrt{5}x-3x-3\sqrt{5}\\ x^2+\sqrt{5}x-3x-3\sqrt{5}$$