Answer
See below
Work Step by Step
The solution of a $3 \times 3$ matrix is $\begin{bmatrix}
1 & 0& -2\\
3 & -4 & 0\\
2 & 0 & 5
\end{bmatrix}\\=-6[(0)(-5)-(-2)(1)]-1[(3)(5)-(-2)(-1)]+8[(3)(1))-(0)(-1)]\\=-1$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 9 Quadratic Relations and Conic Sections - 9.4 Graph and Write Equations of Ellipses - 9.4 Exercises - Mixed Review - Page 639: 57
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