Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - 9.3 Graph and Write Equations of Circles - Guided Practice for Examples 1, 2, and 3 - Page 627: 4

Answer

$x^2+y^2=26$.

Work Step by Step

The standard form of the equation of a circle with a center at the origin and radius $r$ is: $x^2+y^2=r^2$. Plugging in the values of the given point we get: $5^2+(-1)^2=r^2\\26=r^2\\r=\sqrt{26}$ ($r$ cannot be negative). Hence our equation: $x^2+y^2=26$.
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