Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - 9.3 Graph and Write Equations of Circles - 9.3 Exercises - Skill Practice - Page 630: 53

Answer

$y=-\frac{1}{4}x+\frac{17}{4}$

Work Step by Step

From geometry, a line tangent to a circle is perpendicular to the radius at the point of tangency. The radius with endpoint $(1,4)$ has slope $m=\frac{0-4}{0-1}=4$, so the slope of the tangent line at $(1, 4)$ is the negative reciprocal of $4$, or $-\frac{1}{4}$. An equation of the tangent line is as follows: $y-4=-\frac{1}{4}(x-1)\\y=-\frac{1}{4}x+\frac{17}{4}$
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