Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - 9.3 Graph and Write Equations of Circles - 9.3 Exercises - Problem Solving - Page 631: 65c



Work Step by Step

Let it enter the layer at $(x_2,-4)$ and leave at $(x_1,-4)$. As we can see $x_1=-x_2$ Then $x_1^2+(-4)^2=5^2\\x_1^2=9\\x_1=\pm3$ As we can see $x_1$ is positive, thus $x_1=3$. Thus $x_2=-3$. Then the distance is: $|x_1-x_2|=|3-(-3)|=6$
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