Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - 9.3 Graph and Write Equations of Circles - 9.3 Exercises - Mixed Review - Page 632: 83

Answer

$$b=2\sqrt{7},\:b=-2\sqrt{7}$$

Work Step by Step

Solving the equation using the rules of Algebra, we find: $$-b^2=-28 \\ b^2=28\\ b=\sqrt{28},\:b=-\sqrt{28}\\ b=2\sqrt{7},\:b=-2\sqrt{7}$$
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