Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - 9.2 Graph and Write Equations of Parabolas - Guided Practice for Examples 1 and 2 - Page 622: 7

Answer

$y^2=-2x$

Work Step by Step

If the parabola has its vertex at $(0,0)$ and its focus at $(p,0)$ then the equation is: $y^2=4px$. Hence here $p=-2$, thus the equation is: $y^2=-2x$
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