Algebra 2 (1st Edition)

Published by McDougal Littell

Chapter 9 Quadratic Relations and Conic Sections - 9.2 Graph and Write Equations of Parabolas - 9.2 Exercises - Skill Practice - Page 624: 50

Answer

$y^2=\frac{2}{9}x$

Work Step by Step

If the parabola has its vertex at $(0,0)$ and its directrix at $x=-p$ then the equation is: $y^2=4px$. Hence here $p=\frac{1}{18}$, thus the equation is: $y^2=\frac{2}{9}x$

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