Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - 9.1 Apply the Distance and Midpoint Formulas - 9.1 Exercises - Skill Practice - Page 618: 43

Answer

$x=\pm6-4$

Work Step by Step

The distance formula from $P_1(x_1,y_1)$ to $P_2(x_2,y_2)$ is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$. Hence here: $\sqrt{(x-(-4))^2+(7-1)^2}=6\sqrt{2}\\(x+4)^2+36=72\\(x+4)^2=36\\x+4=\pm6\\x=\pm6-4$
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