Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - 9.1 Apply the Distance and Midpoint Formulas - 9.1 Exercises - Problem Solving - Page 619: 53b

Answer

about $1.32$ miles

Work Step by Step

The distance formula from $P_1(x_1,y_1)$ to $P_2(x_2,y_2)$ is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$. Hence here (using part a)): $MS=\sqrt{(-1.5-(-6))^2+(8-5)^2}=\sqrt{29.25}$, $VS=\sqrt{(0-(-6))^2+(0-5)^2}=\sqrt{61}$, thus the total distance: $\sqrt{61}+\sqrt{29.25}\approx13.2$. We know that $1$ mile equals ten units, thus in miles the distance is: $13.2\cdot0.1=1.32$ miles
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