Answer
$\frac{1}{(x+3)^2}$
Work Step by Step
$\frac{x^2-13x+40}{x^2-2x-15}\div(x^2-5x-24)=\frac{x^2-13x+40}{(x^2-2x-15)(x^2-5x-24)}=\frac{(x-5)(x-8)}{(x-5)(x+3)(x-8)(x+3)}=\frac{1}{(x+3)(x+3)}=\frac{1}{(x+3)^2}$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 8 Rational Functions - Chapter Review - Page 605: 22
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