#### Answer

C

#### Work Step by Step

We use cross multiplication to solve the equation. Doing this, we find:
$$2\left(x^2-2x-3\right)=\left(x-3\right)\cdot \:1 \\ x=3,\:x=-\frac{1}{2}$$
Since 3 is an extraneous solution, $-1/2$ is the actual solution.

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Published by
McDougal Littell

ISBN 10:
0618595414

ISBN 13:
978-0-61859-541-9

C

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