Answer
C
Work Step by Step
We use cross multiplication to solve the equation. Doing this, we find:
$$2\left(x^2-2x-3\right)=\left(x-3\right)\cdot \:1 \\ x=3,\:x=-\frac{1}{2}$$
Since 3 is an extraneous solution, $-1/2$ is the actual solution.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 8 Rational Functions - 8.6 Solve Rational Equations - 8.6 Exercises - Skill Practice - Page 593: 28
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