## Algebra 2 (1st Edition)

$f(x)=\frac{-0.27x^3+1.4x^2+1.05x+39.4}{-8.25x^3+53.1x^2-7.82x+138}$
According to the text of the exercise: $f(x)=\frac{g(x)}{h(x)}=\frac{-0.27x^3+1.4x^2+1.05x+39.4}{-8.25x^3+53.1x^2-7.82x+138}$