Algebra 2 (1st Edition)

$$\frac{8x\left(x+1\right)}{\left(5x+3\right)\left(x-2\right)}$$
Simplifying the expression by multiplying the $x-2$ to the denominator: $$\frac{16}{\frac{10x+6}{x\left(x+1\right)}\left(x-2\right)}\\ \frac{16x\left(x+1\right)}{\left(10x+6\right)\left(x-2\right)} \\ \frac{8x\left(x+1\right)}{\left(5x+3\right)\left(x-2\right)}$$