Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - Mixed Review of Problem Solving - Lessons 7.5-7.7 - Page 537: 1c

Answer

See below

Work Step by Step

From part a, we have the scatter plot of $(\ln x, \ln y)$. We can see that the data doesn't fall neatly onto a single line. Use the form: $\ln y-y_1=m(\ln x-x_1)$ Take two points: $(0,5.986);(1.609,6.138)$ Find the slope: $m=\frac{6.138-5.986}{1.609-0}\approx 0.0932$ Obtain: $\ln y-5.986=0.0932(\ln x-0)\\\ln y=0.0932\ln x+6.0792\\\ln y=\ln x^{0.0932+6.0792}\\y=e^{6.0792}(e^{0.0932})^x\\y=463.68(1.09768)^x$
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