Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - 7.7 Write and Apply Exponential and Power Functions - Guided Practice for Example 4 - Page 531: 5


$y=2\cdot x^{\ln_6{3.5}}$

Work Step by Step

Let $y=ax^b$. Then our equations are: $2=a1^b$ and $7=a6^b$. Then $2=a$. Then: $7=26^b\\3.5=6^b\\b=\ln_6{3.5}$. Thus $y=2\cdot x^{\ln_6{3.5}}$
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