## Algebra 2 (1st Edition)

$y=2\cdot x^{\ln_6{3.5}}$
Let $y=ax^b$. Then our equations are: $2=a1^b$ and $7=a6^b$. Then $2=a$. Then: $7=26^b\\3.5=6^b\\b=\ln_6{3.5}$. Thus $y=2\cdot x^{\ln_6{3.5}}$