## Algebra 2 (1st Edition)

$y=0.214\cdot x^{2.389}$
Let $y=ax^b$. Then our equations are: $10=a5^b$ and $81=a12^b$. If we divide the second equation by the first one we get: $8.1=2.4^b\\b=\ln_{2.4}{8.1}\approx2.389$. Then $10=a5^{2.389}\\a=\frac{10}{5^{2.389}}\approx0.214$. Thus $y=0.214\cdot x^{2.389}$