Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - 7.7 Write and Apply Exponential and Power Functions - 7.7 Exercises - Quiz for Lessons 7.6-7.7 - Page 536: 16



Work Step by Step

Plugging in $y=15$ into the formula we get: $15=0.51(1.46)^x\\\frac{15}{0.51}=(1.46)^x\\x=\log_{1.46}{\frac{15}{0.51}}\approx8.935$
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