Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - 7.6 Solve Exponential and Logarithmic Equations - Guided Practice for Examples 4, 5, and 6 - Page 518: 10



Work Step by Step

Using the rules of logarithms to solve the equation, we find: $$\log _4\left(\left(x+12\right)x\right)=3 \\ \log _4\left(\left(x+12\right)x\right)=\log _4\left(64\right) \\ \left(x+12\right)x=64 \\ x=4,\:x=-16$$ Checking for extraneous solutions, we see that only $x=4$ is valid.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.