Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - 7.6 Solve Exponential and Logarithmic Equations - Guided Practice for Examples 2 and 3 - Page 516: 5

Answer

.155

Work Step by Step

Since there is a variable in the exponent on one side of the equation, we use logarithms. Doing this, we find: $$ 9x = log_7 (15) \\ x =\frac{log_7(15)}{9} \\ x=.155$$
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