Answer
See below
Work Step by Step
Let $x=\log_b m\\y=\log_b n$
Rewrite as: $b^x=m\\b^y=n$
Obtain: $\log_b{mn}=\log_b b^xb^y=\log_b b^x b^y=\log_b b^{x+y}=(x+y)\log_b b$
Thus, $x+y=\log_b m+\log_b n\\
\rightarrow \log_b mm=\log_b m+\log_b n$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 7 Exponential and Logarithmic Functions - 7.5 Apply Properties of Logarithms - 7.5 Exercises - Skill Practice - Page 511: 65
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
