Work Step by Step
We know that $x\log_ab=\log_ab^x$ and that $\log_ab+\log_ac=\log_a(bc)$ Hence here $\ln40+2\ln0.5+\ln x=\ln40+\ln0.5^2+\ln x=\ln40+\ln0.25+\ln x=\ln(40\cdot0.25x)=\ln(10x)$
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