Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - 7.1 Graph Exponential Growth Functions - 7.1 Exercises - Skill Practice - Page 483: 28

Answer

$1219(1.12)^x$

Work Step by Step

Let $x$ be the number of years after $1992$. Then our initial amount is $1219$, and the percent increase is: $0.12$. Then the number of parakeets is ($0\leq x\leq11$): $1219(1+0.12)^x=1219(1.12)^x$
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