## Algebra 2 (1st Edition)

Published by McDougal Littell

# Chapter 7 Exponential and Logarithmic Functions - 7.1 Graph Exponential Growth Functions - 7.1 Exercises - Skill Practice - Page 483: 28

#### Answer

$1219(1.12)^x$

#### Work Step by Step

Let $x$ be the number of years after $1992$. Then our initial amount is $1219$, and the percent increase is: $0.12$. Then the number of parakeets is ($0\leq x\leq11$): $1219(1+0.12)^x=1219(1.12)^x$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.