Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 6 Rational Exponents and Radical Functions - 6.6 Solve Radical Equations - 6.6 Exercises - Problem Solving - Page 459: 62



Work Step by Step

Plugging in $l=5,b_1=2,b_2=4$ into the formula we get: $5=\sqrt{h^2+0.25(4-2)^2}=\sqrt{h^2+0.25(2)^2}=\sqrt{h^2+0.25(4)}=\sqrt{h^2+1}\\25=h^2+1\\24=h^2\\h=2\sqrt{6}$
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