Answer
$h=2\sqrt{6}$
Work Step by Step
Plugging in $l=5,b_1=2,b_2=4$ into the formula we get: $5=\sqrt{h^2+0.25(4-2)^2}=\sqrt{h^2+0.25(2)^2}=\sqrt{h^2+0.25(4)}=\sqrt{h^2+1}\\25=h^2+1\\24=h^2\\h=2\sqrt{6}$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 6 Rational Exponents and Radical Functions - 6.6 Solve Radical Equations - 6.6 Exercises - Problem Solving - Page 459: 62
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