## Algebra 2 (1st Edition)

$$x=2\sqrt{3}+3,\:x=-2\sqrt{3}+3$$
Solving the equation by isolating $x$, we find: $$9\left(x-3\right)^2=108 \\ \left(x-3\right)^2=12 \\ x=2\sqrt{3}+3,\:x=-2\sqrt{3}+3$$