Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 6 Rational Exponents and Radical Functions - 6.4 Use Inverse Functions - 6.4 Exercises - Quiz for Lessons 6.3-6.4 - Page 445: 14

Answer

$$y=\sqrt{x+16},\:y=-\sqrt{x+16}$$

Work Step by Step

Switching the elements of the domain and the range (in other words, the dependent and independent variables), we find that the inverse is: $$x=y^2-16 \\ y=\sqrt{x+16},\:y=-\sqrt{x+16}$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.