Answer
See below.
Work Step by Step
In this case $(x^2-3)(4x)$ doesn't mean multiplication but plugging in $4x$ into $x$, which leads us to: $(4x)^2-3=16x^2-3$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 6 Rational Exponents and Radical Functions - 6.3 Perform Function Operations and Composition - 6.3 Exercises - Skill Practice - Page 432: 36
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