Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 6 Rational Exponents and Radical Functions - 6.3 Perform Function Operations and Composition - 6.3 Exercises - Problem Solving - Page 434: 47b

Answer

See below

Work Step by Step

$\sqrt 2\approx1.414213562$ From part a, we have: $f(x)=\frac{x+\frac{n}{x}}{2}$ $f(1)=\frac{1+\frac{2}{1}}{2}=\frac{3}{2}$ $f(\frac{3}{2})=\frac{\frac{3}{2}+\frac{3}{\frac{3}{2}}}{2}\approx1.4167$ $f(1.4167)=\frac{1.467+\frac{2}{1.467}}{2}\approx1.415$ $f(1.415)=\frac{1.415+\frac{2}{1.415}}{2}\approx1.414$ We can see that the sixth decimal becomes constant starting with the fourth step.
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