Chapter 6 Rational Exponents and Radical Functions - 6.1 Evaluate nth Roots and Use Rational Exponents - 6.1 Exercises - Mixed Review - Page 419: 70

The zeros are $4+3i$ or $4-3i$

Given: $f(x)=x^2-8x+25$ Let $f(x)=0$, $x^2-8x+25=0$ The solution to this equation is: $x=\frac{-b\pm \sqrt b^2-4ac}{2a}=\frac{-(-8)\pm\sqrt (-8)^2-4(1)(25)}{2(1)}=\frac{8\pm \sqrt -36}{2}=\frac{8\pm 6i}{2}=4\pm 3i$ Hence, the zeros are $4+3i$ or $4-3i$.