## Algebra 2 (1st Edition)

$$x^3-6x^2+5x+12$$
Starting with the factors in order to find the original polynomial function, we find: $$\left(x+1\right)\left(x-3\right)\left(x-4\right) \\ \left(x^2-2x-3\right)\left(x-4\right) \\ x^3-6x^2+5x+12$$