Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 5 Polynomials and Polynomial Functions - 5.9 Write Polynomial Functions and Models - 5.9 Exercises - Skill Practice - Page 397: 7



Work Step by Step

Here, we have $f(x)=a (x-(-2))(x-(-1))(x-2)$ or, $f(x)=a (x+2)(x+1)(x-2)$ When $x=0$, then we have $-8=a (0+2)(0+1)(0-2)$ or, $-4a=-8$ This gives: $a=2$ Thus, we have $f(x)=2(x+2)(x+1)(x-2)$
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