# Chapter 5 Polynomials and Polynomial Functions - 5.9 Write Polynomial Functions and Models - 5.9 Exercises - Skill Practice - Page 397: 7

$f(x)=2(x+2)(x+1)(x-2)$

#### Work Step by Step

Here, we have $f(x)=a (x-(-2))(x-(-1))(x-2)$ or, $f(x)=a (x+2)(x+1)(x-2)$ When $x=0$, then we have $-8=a (0+2)(0+1)(0-2)$ or, $-4a=-8$ This gives: $a=2$ Thus, we have $f(x)=2(x+2)(x+1)(x-2)$

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