## Algebra 2 (1st Edition)

$x=5$, $x=-4$ or $x=\pm\frac{3}{\sqrt2}$
$f(x)=2x^4-2x^3-49x^2+9x+180=(x-5)(x+4)(2x^2-9)=0$ Thus $x=5$, $x=-4$ or $x=\pm\frac{3}{\sqrt2}$