Answer
$f(x)=x^3-5x^2+2x+8$
Work Step by Step
Using the Factor Theorem, if $x=a$ is a factor, then $(x-a)$ is a factor of $f(x)$.
Hence here $f(x)=(x+1)(x-2)(x-4)=(x+1)(x^2-2x-4x+8)=(x+1)(x^2-6x+8)=x^3-6x^2+8x+x^2-6x+8=x^3-5x^2+2x+8$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 5 Polynomials and Polynomial Functions - 5.7 Apply the Fundamental Theorem of Algebra - Guided Practice for Example 3 - Page 381: 5
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