## Algebra 2 (1st Edition)

$g\approx 1.04842$ and $r\approx 0.04842$
Here, we have $V(g)=1000g^3+1000g^2+1000g+1000=4300$ or, $g^3+g^2+g-3.3=0$ Thus, the function is $f(x)=x^3+x^2+x-3.3$ Thus, $x\approx 1.04842$ The real solution of the equation is $g\approx 1.04842$ Now, we have $g=1+r$ Then $1+r \approx 1.04842$ This gives: $r\approx 0.04842$ Hence, $g\approx 1.04842$ and $r\approx 0.04842$