Answer
$z=\frac{1}{7}$
Work Step by Step
Given: $49z^2-14z+1=0$
Rewrite as: $(7z)^2-2.(7z).(1)+(1)^2=0$
It is equal to: $(7z-1)^2=0$
Solve for z: $7z-1=0$
Then, $z=\frac{1}{7}$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 5 Polynomials and Polynomial Functions - 5.6 Find Rational Zeroes - 5.6 Exercises - Mixed Review - Page 377: 55
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