Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 5 Polynomials and Polynomial Functions - 5.6 Find Rational Zeroes - 5.6 Exercises - Mixed Review - Page 377: 55



Work Step by Step

Given: $49z^2-14z+1=0$ Rewrite as: $(7z)^2-2.(7z).(1)+(1)^2=0$ It is equal to: $(7z-1)^2=0$ Solve for z: $7z-1=0$ Then, $z=\frac{1}{7}$
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