$3$ and $-3$.
Work Step by Step
Since $f(-2)=0$, $(x+2)$ is a factor of $f(x)$. Thus $f(x)=(x+2)(x^2-9)=(x+2)(x+3)(x-3)$ Thus the other zeros are $3$ and $-3$.
You can help us out by revising, improving and updating this answer.Update this answer
After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.