Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 5 Polynomials and Polynomial Functions - 5.5 Apply the Remainder and Factor Theorems - Guided Practice for Examples 5 and 6 - Page 365: 7

Answer

$3$ and $-3$.

Work Step by Step

Since $f(-2)=0$, $(x+2)$ is a factor of $f(x)$. Thus $f(x)=(x+2)(x^2-9)=(x+2)(x+3)(x-3)$ Thus the other zeros are $3$ and $-3$.
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