Answer
$$2x^2-3x+8+\frac{-18x+7}{x^2+2x-1}$$
Work Step by Step
Dividing the two polynomials using long division, we find:
$$2x^2+\frac{-3x^3+2x^2+x-1}{x^2+2x-1} \\ 2x^2-3x+\frac{8x^2-2x-1}{x^2+2x-1} \\ 2x^2-3x+8+\frac{-18x+7}{x^2+2x-1}$$
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