Answer
$x=2$ or $x=-3$ or $x=6$
Work Step by Step
From the earlier parts: $f(x)=x^3−5x^2−12x+36=(x−2)(x+3)(x−6)$. Thus $f(x)=(x−2)(x+3)(x−6)=0$
Thus $x-2=0\\x=2$ or $x+3=0\\x=-3$ or $x-6=0\\x=6$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 5 Polynomials and Polynomial Functions - 5.5 Apply the Remainder and Factor Theorems - 5.5 Exercises - Skill Practice - Page 356: 38c
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