Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 5 Polynomials and Polynomial Functions - 5.4 Factor and Solve Polynomial Equations - 5.4 Exercises - Problem Solving - Page 359: 64b



Work Step by Step

Calculate $y^3+y^2$ for $y=1,2,...,10$ Solve $x^3+2x^2=96\\ \Leftrightarrow (\frac{x}{2})^3+(\frac{x}{2})^2=\frac{96}{8}=12$ Search for values of $12$ in the table. It matches $y=2$. Hence, $\frac{x}{2}=2 \rightarrow x=4$
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