Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 5 Polynomials and Polynomial Functions - 5.4 Factor and Solve Polynomial Equations - 5.4 Exercises - Problem Solving - Page 358: 61


$5$ in high and wide, and $10$ in long.

Work Step by Step

Let $x$ be the height and the width; then the length is $x+5$. Then our equation is: $x\cdot x\cdot (x+5)=250\\x^3+5x^2-250=0\\(x-5)(x^2+10x+5)=0$ The second term in the product has a positive discriminant, thus it cannot be $0$. Thus $x-5=0\\x=5$. Thus the prism is $5$ inches high and wide, and $10$ in long.
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