Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 5 Polynomials and Polynomial Functions - 5.3 Add, Subtract, and Multiply Polynomials - 5.3 Exercises - Skill Practice - Page 350: 49


$2\pi x^3-13\pi x^2+8\pi x+48\pi$

Work Step by Step

Plugging in the values we get: $V=\pi(x-4)(x-4)(2x+3)=\pi(x^2-4x-4x+16)(2x+3)=\pi(x^2-8x+16)(2x+3)=\pi(2x^3-16x^2+32x+3x^2-24x+48)=\pi(2x^3-13x^2+8x+48)=2\pi x^3-13\pi x^2+8\pi x+48\pi$
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