## Algebra 2 (1st Edition)

$q=-\frac{7}{2}$ or $q=-\frac{1}{4}$
Set up the function: $-24q^2-90q-21=0$ with $a=-24, b=-90, c=-21$ Find $q$ by using: $q=\frac{-b \pm \sqrt b^2-4ac}{2a}=\frac{-(-90)\pm\sqrt (-90)^2-4.(-24).(-21)}{2.(-24)}=\frac{90\pm78}{-48}$ $q=\frac{90+78}{-48}$ or $x=\frac{90-78}{-48}$ $q=-\frac{7}{2}$ or $q=-\frac{1}{4}$