Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - Standardized Test Practice - Extended Response - Page 327: 22a

Answer

See below

Work Step by Step

Let $h$ be a downward opening parabola Find t: $t=-\frac{b}{2a}=-\frac{30}{2(-16)}=\frac{15}{16}$ Then we have: $h=-16(\frac{15}{16})^2+30(\frac{15}{16})+6=\frac{321}{16} \approx20.0625\approx20.1$
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