Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - Mixed Review of Problem Solving - Lessons 4.6-4.10 - Page 316: 7a

Answer

See below

Work Step by Step

The height of the ball can be expressed as: $h=h_0+v_0t-16t^2$ Given: $v_0=50\\h_0=5$ Substitute: $h=5+50t-16t^2$
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